z-2=3(14+3z)-12

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Solution for z-2=3(14+3z)-12 equation: 



z-2=3(14+3z)-12

We move all terms to the left:

z-2-(3(14+3z)-12)=0

We add all the numbers together, and all the variables

z-(3(3z+14)-12)-2=0



We calculate terms in parentheses: -(3(3z+14)-12), so:

3(3z+14)-12

We multiply parentheses

9z+42-12

We add all the numbers together, and all the variables

9z+30

Back to the equation:

-(9z+30)



We get rid of parentheses

z-9z-30-2=0

We add all the numbers together, and all the variables

-8z-32=0

We move all terms containing z to the left, all other terms to the right

-8z=32

z=32/-8

z=-4

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