1/5(20-5x)=-2(-2-x)=3

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Solution for 1/5(20-5x)=-2(-2-x)=3 equation: 



1/5(20-5x)=-2(-2-x)=3

We move all terms to the left:

1/5(20-5x)-(-2(-2-x))=0



Domain of the equation: 5(20-5x)!=0

x∈R



We add all the numbers together, and all the variables

1/5(-5x+20)-(-2(-1x-2))=0

We multiply all the terms by the denominator


-((-2(-1x-2)))*5(-5x+20)+1=0



We calculate terms in parentheses: -((-2(-1x-2)))*5(-5x+20), so:

(-2(-1x-2)))*5(-5x+20

We add all the numbers together, and all the variables

-5x+(-2(-1x-2)))*5(+20

Back to the equation:

-(-5x+(-2(-1x-2)))*5(+20)



We add all the numbers together, and all the variables

-(-5x+(-2(-1x-2)))*520+1=0

We move all terms containing x to the left, all other terms to the right

-(-5x+(-2(-1x-2)))*520=-1

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