(6x-3)(2x-1)=0

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Solution for (6x-3)(2x-1)=0 equation: 



(6x-3)(2x-1)=0

We multiply parentheses ..

(+12x^2-6x-6x+3)=0

We get rid of parentheses

12x^2-6x-6x+3=0

We add all the numbers together, and all the variables

12x^2-12x+3=0

a = 12; b = -12; c = +3;
Δ = b2-4ac
Δ = -122-4·12·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{24}=1/2$

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