z-2(z-4)=12

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Solution for z-2(z-4)=12 equation: 



z-2(z-4)=12

We move all terms to the left:

z-2(z-4)-(12)=0

We multiply parentheses

z-2z+8-12=0

We add all the numbers together, and all the variables

-1z-4=0

We move all terms containing z to the left, all other terms to the right

-z=4

z=4/-1

z=-4

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