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2(x-5)=6(2-1/2x)
We move all terms to the left:
2(x-5)-(6(2-1/2x))=0
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(x-5)-(6(-1/2x+2))=0
We multiply parentheses
2x-(6(-1/2x+2))-10=0
We multiply all the terms by the denominator
2x*2x-10*2x-1+2))-(6(+2))=0
We add all the numbers together, and all the variables
2x*2x-10*2x-1+2))-(62)=0
We add all the numbers together, and all the variables
2x*2x-10*2x=0
Wy multiply elements
4x^2-20x=0
a = 4; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·4·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*4}=\frac{40}{8} =5 $
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