z-12=2(6-z)-3(z-6)

Solution for z-12=2(6-z)-3(z-6) equation:

z-12=2(6-z)-3(z-6)

We move all terms to the left:

z-12-(2(6-z)-3(z-6))=0

We add all the numbers together, and all the variables

z-(2(-1z+6)-3(z-6))-12=0


We calculate terms in parentheses: -(2(-1z+6)-3(z-6)), so:

2(-1z+6)-3(z-6)

We multiply parentheses

-2z-3z+12+18

We add all the numbers together, and all the variables

-5z+30

Back to the equation:

-(-5z+30)


We get rid of parentheses

z+5z-30-12=0

We add all the numbers together, and all the variables

6z-42=0

We move all terms containing z to the left, all other terms to the right

6z=42

z=42/6

z=7