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(4x-10/2=x+7
We move all terms to the left:
(4x-10/2-(x+7)=0
Domain of the equation: 2-(x+7)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(x+7)!=-2
x∈R
(4x-10=0
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