z+(4/z+1))=3

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Solution for z+(4/z+1))=3 equation: 



z+(4/z+1))=3

We move all terms to the left:

z+(4/z+1))-(3)=0



Domain of the equation: z+1))-3!=0

z∈R



We multiply all the terms by the denominator


z*z+1))-3+(4=0

We add all the numbers together, and all the variables

z*z=0

Wy multiply elements

z^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{2}=0$

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