z(2+i)=3-i

Solution for z(2+i)=3-i equation:

Simplifying
z(2 + i) = 3 + -1i
(2 * z + i * z) = 3 + -1i

Reorder the terms:
(iz + 2z) = 3 + -1i
(iz + 2z) = 3 + -1i

Solving
iz + 2z = 3 + -1i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'i' to each side of the equation.
iz + i + 2z = 3 + -1i + i

Reorder the terms:
i + iz + 2z = 3 + -1i + i

Combine like terms: -1i + i = 0
i + iz + 2z = 3 + 0
i + iz + 2z = 3

Add '-2z' to each side of the equation.
i + iz + 2z + -2z = 3 + -2z

Combine like terms: 2z + -2z = 0
i + iz + 0 = 3 + -2z
i + iz = 3 + -2z

Reorder the terms:
-3 + i + iz + 2z = 3 + -2z + -3 + 2z

Reorder the terms:
-3 + i + iz + 2z = 3 + -3 + -2z + 2z

Combine like terms: 3 + -3 = 0
-3 + i + iz + 2z = 0 + -2z + 2z
-3 + i + iz + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-3 + i + iz + 2z = 0

The solution to this equation could not be determined.