y=2/3X+16

Solution for y=2/3X+16 equation:

y=2/3y+16

We move all terms to the left:

y-(2/3y+16)=0


Domain of the equation: 3y+16)!=0

y∈R


We get rid of parentheses

y-2/3y-16=0

We multiply all the terms by the denominator


y*3y-16*3y-2=0

Wy multiply elements

3y^2-48y-2=0

a = 3; b = -48; c = -2;
Δ = b2-4ac
Δ = -482-4·3·(-2)
Δ = 2328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2328}=\sqrt{4*582}=\sqrt{4}*\sqrt{582}=2\sqrt{582}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-2\sqrt{582}}{2*3}=\frac{48-2\sqrt{582}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+2\sqrt{582}}{2*3}=\frac{48+2\sqrt{582}}{6}
$