6z=4(1/2z-32

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Solution for 6z=4(1/2z-32 equation: 



6z=4(1/2z-32

We move all terms to the left:

6z-(4(1/2z-32)=0



Domain of the equation: 2z-32)!=0

z∈R



We multiply all the terms by the denominator


6z*2z-32)-(4(1=0

We add all the numbers together, and all the variables

6z*2z=0

Wy multiply elements

12z^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{24}=0$

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