y=1/6x;y=1/3x-1

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Solution for y=1/6x;y=1/3x-1 system of equations: 


  • /| y-((1/6)*x) = 0| y-((1/3)*x)+1 = 0
  • We try to solve the equation: y-((1/6)*x) = 0
  • y-1/6*x = 0 // + -1/6*x
  • y = -(-1/6*x)
  • y = 1/6*x
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 1/6*x-((1/3)*x)+1 = 0| y = 1/6*x
  • 1-1/6*x = 0 // - 1
  • -1/6*x = -1 // : -1/6
  • x = -1/(-1/6)
  • x = 6
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 1/6*x: 
  • y = 1/6*6
  • y = 1
  • We get a system of equations:
  • /| y = 1| x = 6

 

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