y=-3/2x-1;y=1/4x+6

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Solution for y=-3/2x-1;y=1/4x+6 system of equations: 


  • /| y-((-3/2)*x)+1 = 0| y-((1/4)*x)-6 = 0
  • We try to solve the equation: y-((-3/2)*x)+1 = 0
  • 3/2*x+y+1 = 0 // - 3/2*x+1
  • y = -(3/2*x+1)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| -((1/4)*x)-(3/2*x)-6-1 = 0| y = -(3/2*x+1)
  • -7/4*x-7 = 0 // + 7
  • -7/4*x = 7 // : -7/4
  • x = 7/(-7/4)
  • x = -4
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -(3/2*x+1): 
  • y = -(1-4*3/2)
  • y = -(1-6)
  • y = 5
  • We get a system of equations:
  • /| y = 5| x = -4

 

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