y=1-20(3y^2-y+10)

Solution for y=1-20(3y^2-y+10) equation:

y=1-20(3y^2-y+10)

We move all terms to the left:

y-(1-20(3y^2-y+10))=0


We calculate terms in parentheses: -(1-20(3y^2-y+10)), so:

1-20(3y^2-y+10)

determiningTheFunctionDomain
-20(3y^2-y+10)+1

We multiply parentheses

-60y^2+20y-200+1

We add all the numbers together, and all the variables

-60y^2+20y-199

Back to the equation:

-(-60y^2+20y-199)


We get rid of parentheses

60y^2-20y+y+199=0

We add all the numbers together, and all the variables

60y^2-19y+199=0

a = 60; b = -19; c = +199;
Δ = b2-4ac
Δ = -192-4·60·199
Δ = -47399
Delta is less than zero, so there is no solution for the equation