y=1-20(3y-y+10)

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Solution for y=1-20(3y-y+10) equation: 



y=1-20(3y-y+10)

We move all terms to the left:

y-(1-20(3y-y+10))=0

We add all the numbers together, and all the variables

y-(1-20(2y+10))=0



We calculate terms in parentheses: -(1-20(2y+10)), so:

1-20(2y+10)

determiningTheFunctionDomain
-20(2y+10)+1

We multiply parentheses

-40y-200+1

We add all the numbers together, and all the variables

-40y-199

Back to the equation:

-(-40y-199)



We get rid of parentheses

y+40y+199=0

We add all the numbers together, and all the variables

41y+199=0

We move all terms containing y to the left, all other terms to the right

41y=-199

y=-199/41

y=-4+35/41

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