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y2-411=0
We add all the numbers together, and all the variables
y^2-411=0
a = 1; b = 0; c = -411;
Δ = b2-4ac
Δ = 02-4·1·(-411)
Δ = 1644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1644}=\sqrt{4*411}=\sqrt{4}*\sqrt{411}=2\sqrt{411}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{411}}{2*1}=\frac{0-2\sqrt{411}}{2} =-\frac{2\sqrt{411}}{2} =-\sqrt{411} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{411}}{2*1}=\frac{0+2\sqrt{411}}{2} =\frac{2\sqrt{411}}{2} =\sqrt{411} $
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