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5(x+4)=3(x-3)+5
We move all terms to the left:
5(x+4)-(3(x-3)+5)=0
We multiply parentheses
5x-(3(x-3)+5)+20=0
We calculate terms in parentheses: -(3(x-3)+5), so:We get rid of parentheses
3(x-3)+5
We multiply parentheses
3x-9+5
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
5x-3x+4+20=0
We add all the numbers together, and all the variables
2x+24=0
We move all terms containing x to the left, all other terms to the right
2x=-24
x=-24/2
x=-12
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