y2+58y+840=0

Solution for y2+58y+840=0 equation:

y2+58y+840=0

We add all the numbers together, and all the variables

y^2+58y+840=0

a = 1; b = 58; c = +840;
Δ = b2-4ac
Δ = 582-4·1·840
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-2}{2*1}=\frac{-60}{2}
=-30
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+2}{2*1}=\frac{-56}{2}
=-28
$