(11z+6)=(4z-4)

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Solution for (11z+6)=(4z-4) equation: 



(11z+6)=(4z-4)

We move all terms to the left:

(11z+6)-((4z-4))=0

We get rid of parentheses

11z-((4z-4))+6=0



We calculate terms in parentheses: -((4z-4)), so:

(4z-4)

We get rid of parentheses

4z-4

Back to the equation:

-(4z-4)



We get rid of parentheses

11z-4z+4+6=0

We add all the numbers together, and all the variables

7z+10=0

We move all terms containing z to the left, all other terms to the right

7z=-10

z=-10/7

z=-1+3/7

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