y2+32y-273=0

Solution for y2+32y-273=0 equation:

y2+32y-273=0

We add all the numbers together, and all the variables

y^2+32y-273=0

a = 1; b = 32; c = -273;
Δ = b2-4ac
Δ = 322-4·1·(-273)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-46}{2*1}=\frac{-78}{2}
=-39
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+46}{2*1}=\frac{14}{2}
=7
$