2r+3r=3(2r-3)

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Solution for 2r+3r=3(2r-3) equation: 



2r+3r=3(2r-3)

We move all terms to the left:

2r+3r-(3(2r-3))=0

We add all the numbers together, and all the variables

5r-(3(2r-3))=0



We calculate terms in parentheses: -(3(2r-3)), so:

3(2r-3)

We multiply parentheses

6r-9

Back to the equation:

-(6r-9)



We get rid of parentheses

5r-6r+9=0

We add all the numbers together, and all the variables

-1r+9=0

We move all terms containing r to the left, all other terms to the right

-r=-9

r=-9/-1

r=+9

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