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3(x-3)=-2(1+2x)
We move all terms to the left:
3(x-3)-(-2(1+2x))=0
We add all the numbers together, and all the variables
3(x-3)-(-2(2x+1))=0
We multiply parentheses
3x-(-2(2x+1))-9=0
We calculate terms in parentheses: -(-2(2x+1)), so:We get rid of parentheses
-2(2x+1)
We multiply parentheses
-4x-2
Back to the equation:
-(-4x-2)
3x+4x+2-9=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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