y2+23y+102=0

Solution for y2+23y+102=0 equation:

y2+23y+102=0

We add all the numbers together, and all the variables

y^2+23y+102=0

a = 1; b = 23; c = +102;
Δ = b2-4ac
Δ = 232-4·1·102
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-11}{2*1}=\frac{-34}{2}
=-17
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+11}{2*1}=\frac{-12}{2}
=-6
$