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y/5y-9=8-2y
We move all terms to the left:
y/5y-9-(8-2y)=0
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
y/5y-(-2y+8)-9=0
We get rid of parentheses
y/5y+2y-8-9=0
We multiply all the terms by the denominator
y+2y*5y-8*5y-9*5y=0
Wy multiply elements
10y^2+y-40y-45y=0
We add all the numbers together, and all the variables
10y^2-84y=0
a = 10; b = -84; c = 0;
Δ = b2-4ac
Δ = -842-4·10·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-84}{2*10}=\frac{0}{20} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+84}{2*10}=\frac{168}{20} =8+2/5 $
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