(X+4)(x-7)=5+x(x-4)

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Solution for (X+4)(x-7)=5+x(x-4) equation: 



(X+4)(X-7)=5+X(X-4)

We move all terms to the left:

(X+4)(X-7)-(5+X(X-4))=0

We multiply parentheses ..

(+X^2-7X+4X-28)-(5+X(X-4))=0



We calculate terms in parentheses: -(5+X(X-4)), so:

5+X(X-4)

determiningTheFunctionDomain
X(X-4)+5

We multiply parentheses

X^2-4X+5

Back to the equation:

-(X^2-4X+5)



We get rid of parentheses

X^2-X^2-7X+4X+4X-28-5=0

We add all the numbers together, and all the variables

X-33=0

We move all terms containing X to the left, all other terms to the right

X=33

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