y-5=2(10+3y)

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Solution for y-5=2(10+3y) equation: 



y-5=2(10+3y)

We move all terms to the left:

y-5-(2(10+3y))=0

We add all the numbers together, and all the variables

y-(2(3y+10))-5=0



We calculate terms in parentheses: -(2(3y+10)), so:

2(3y+10)

We multiply parentheses

6y+20

Back to the equation:

-(6y+20)



We get rid of parentheses

y-6y-20-5=0

We add all the numbers together, and all the variables

-5y-25=0

We move all terms containing y to the left, all other terms to the right

-5y=25

y=25/-5

y=-5

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