2(t-3)+2=2(t-4)

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Solution for 2(t-3)+2=2(t-4) equation:



2(t-3)+2=2(t-4)
We move all terms to the left:
2(t-3)+2-(2(t-4))=0
We multiply parentheses
2t-(2(t-4))-6+2=0
We calculate terms in parentheses: -(2(t-4)), so:
2(t-4)
We multiply parentheses
2t-8
Back to the equation:
-(2t-8)
We add all the numbers together, and all the variables
2t-(2t-8)-4=0
We get rid of parentheses
2t-2t+8-4=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation

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