y-(7-8y)/9y-(3+4y)=2/3

Solution for y-(7-8y)/9y-(3+4y)=2/3 equation:

y-(7-8y)/9y-(3+4y)=2/3

We move all terms to the left:

y-(7-8y)/9y-(3+4y)-(2/3)=0


Domain of the equation: 9y!=0

y!=0/9

y!=0

y∈R


We add all the numbers together, and all the variables

y-(-8y+7)/9y-(4y+3)-(+2/3)=0

We get rid of parentheses

y-(-8y+7)/9y-4y-3-2/3=0

We calculate fractions


y-4y+(24y-21)/27y+(-18y)/27y-3=0

We add all the numbers together, and all the variables

-3y+(24y-21)/27y+(-18y)/27y-3=0

We multiply all the terms by the denominator


-3y*27y+(24y-21)+(-18y)-3*27y=0

Wy multiply elements

-81y^2+(24y-21)+(-18y)-81y=0

We get rid of parentheses

-81y^2+24y-18y-81y-21=0

We add all the numbers together, and all the variables

-81y^2-75y-21=0

a = -81; b = -75; c = -21;
Δ = b2-4ac
Δ = -752-4·(-81)·(-21)
Δ = -1179
Delta is less than zero, so there is no solution for the equation