4(2w+2)=7(w-1)+17

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Solution for 4(2w+2)=7(w-1)+17 equation: 



4(2w+2)=7(w-1)+17

We move all terms to the left:

4(2w+2)-(7(w-1)+17)=0

We multiply parentheses

8w-(7(w-1)+17)+8=0



We calculate terms in parentheses: -(7(w-1)+17), so:

7(w-1)+17

We multiply parentheses

7w-7+17

We add all the numbers together, and all the variables

7w+10

Back to the equation:

-(7w+10)



We get rid of parentheses

8w-7w-10+8=0

We add all the numbers together, and all the variables

w-2=0

We move all terms containing w to the left, all other terms to the right

w=2

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