y+4(2y-2)=10-6(y+4)

Solution for y+4(2y-2)=10-6(y+4) equation:

y+4(2y-2)=10-6(y+4)

We move all terms to the left:

y+4(2y-2)-(10-6(y+4))=0

We multiply parentheses

y+8y-(10-6(y+4))-8=0


We calculate terms in parentheses: -(10-6(y+4)), so:

10-6(y+4)

determiningTheFunctionDomain
-6(y+4)+10

We multiply parentheses

-6y-24+10

We add all the numbers together, and all the variables

-6y-14

Back to the equation:

-(-6y-14)


We add all the numbers together, and all the variables

9y-(-6y-14)-8=0

We get rid of parentheses

9y+6y+14-8=0

We add all the numbers together, and all the variables

15y+6=0

We move all terms containing y to the left, all other terms to the right

15y=-6

y=-6/15

y=-2/5