y+2/y=5/3

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Solution for y+2/y=5/3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+2/y = 5/3 // - 5/3

y+2/y-(5/3) = 0

y+2/y-5/3 = 0

1*y^1+2*y^-1-5/3*y^0 = 0

(1*y^2-5/3*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2-5/3*y^1+2*y^0) = 0

y^1

y^2+(-5/3)*y+2 = 0

y^2+(-5/3)*y+2 = 0

DELTA = (-5/3)^2-(1*2*4)

DELTA = -47/9

DELTA < 0

y in { } 

y belongs to the empty set

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