4(d-4)+2=(d+1)

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Solution for 4(d-4)+2=(d+1) equation:


Simplifying
4(d + -4) + 2 = (d + 1)

Reorder the terms:
4(-4 + d) + 2 = (d + 1)
(-4 * 4 + d * 4) + 2 = (d + 1)
(-16 + 4d) + 2 = (d + 1)

Reorder the terms:
-16 + 2 + 4d = (d + 1)

Combine like terms: -16 + 2 = -14
-14 + 4d = (d + 1)

Reorder the terms:
-14 + 4d = (1 + d)

Remove parenthesis around (1 + d)
-14 + 4d = 1 + d

Solving
-14 + 4d = 1 + d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1d' to each side of the equation.
-14 + 4d + -1d = 1 + d + -1d

Combine like terms: 4d + -1d = 3d
-14 + 3d = 1 + d + -1d

Combine like terms: d + -1d = 0
-14 + 3d = 1 + 0
-14 + 3d = 1

Add '14' to each side of the equation.
-14 + 14 + 3d = 1 + 14

Combine like terms: -14 + 14 = 0
0 + 3d = 1 + 14
3d = 1 + 14

Combine like terms: 1 + 14 = 15
3d = 15

Divide each side by '3'.
d = 5

Simplifying
d = 5

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