y+1=2(y-3)-3(y+1)

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Solution for y+1=2(y-3)-3(y+1) equation: 



y+1=2(y-3)-3(y+1)

We move all terms to the left:

y+1-(2(y-3)-3(y+1))=0



We calculate terms in parentheses: -(2(y-3)-3(y+1)), so:

2(y-3)-3(y+1)

We multiply parentheses

2y-3y-6-3

We add all the numbers together, and all the variables

-1y-9

Back to the equation:

-(-1y-9)



We get rid of parentheses

y+1y+9+1=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5

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