2+(3x-4)=20-(2x+3)+(3x+6)

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Solution for 2+(3x-4)=20-(2x+3)+(3x+6) equation: 



2+(3x-4)=20-(2x+3)+(3x+6)

We move all terms to the left:

2+(3x-4)-(20-(2x+3)+(3x+6))=0

We get rid of parentheses

3x-(20-(2x+3)+(3x+6))-4+2=0



We calculate terms in parentheses: -(20-(2x+3)+(3x+6)), so:

20-(2x+3)+(3x+6)

determiningTheFunctionDomain
-(2x+3)+(3x+6)+20

We get rid of parentheses

-2x+3x-3+6+20

We add all the numbers together, and all the variables

x+23

Back to the equation:

-(x+23)



We add all the numbers together, and all the variables

3x-(x+23)-2=0

We get rid of parentheses

3x-x-23-2=0

We add all the numbers together, and all the variables

2x-25=0

We move all terms containing x to the left, all other terms to the right

2x=25

x=25/2

x=12+1/2

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