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y+16=1/3(10y-4)
We move all terms to the left:
y+16-(1/3(10y-4))=0
Domain of the equation: 3(10y-4))!=0We multiply all the terms by the denominator
y∈R
y*3(10y-4))-(1+16*3(10y-4))=0
Wy multiply elements
3y^2(1+48y(1=0
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