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y+1/3y=180
We move all terms to the left:
y+1/3y-(180)=0
Domain of the equation: 3y!=0We multiply all the terms by the denominator
y!=0/3
y!=0
y∈R
y*3y-180*3y+1=0
Wy multiply elements
3y^2-540y+1=0
a = 3; b = -540; c = +1;
Δ = b2-4ac
Δ = -5402-4·3·1
Δ = 291588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291588}=\sqrt{8836*33}=\sqrt{8836}*\sqrt{33}=94\sqrt{33}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-94\sqrt{33}}{2*3}=\frac{540-94\sqrt{33}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+94\sqrt{33}}{2*3}=\frac{540+94\sqrt{33}}{6} $
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