5(x-3)+2=3(x-1)4x

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Solution for 5(x-3)+2=3(x-1)4x equation: 



5(x-3)+2=3(x-1)4x

We move all terms to the left:

5(x-3)+2-(3(x-1)4x)=0

We multiply parentheses

5x-(3(x-1)4x)-15+2=0



We calculate terms in parentheses: -(3(x-1)4x), so:

3(x-1)4x

We multiply parentheses

12x^2-12x

Back to the equation:

-(12x^2-12x)



We add all the numbers together, and all the variables

5x-(12x^2-12x)-13=0

We get rid of parentheses

-12x^2+5x+12x-13=0

We add all the numbers together, and all the variables

-12x^2+17x-13=0

a = -12; b = 17; c = -13;
Δ = b2-4ac
Δ = 172-4·(-12)·(-13)
Δ = -335
Delta is less than zero, so there is no solution for the equation

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