y+(3y-5)=27

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Solution for y+(3y-5)=27 equation: 



y+(3y-5)=27

We move all terms to the left:

y+(3y-5)-(27)=0

We get rid of parentheses

y+3y-5-27=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8

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