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81x^2-18x=-1
We move all terms to the left:
81x^2-18x-(-1)=0
We add all the numbers together, and all the variables
81x^2-18x+1=0
a = 81; b = -18; c = +1;
Δ = b2-4ac
Δ = -182-4·81·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{18}{162}=1/9$
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