4(j+1)+3=19

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Solution for 4(j+1)+3=19 equation: 



4(j+1)+3=19

We move all terms to the left:

4(j+1)+3-(19)=0

We add all the numbers together, and all the variables

4(j+1)-16=0

We multiply parentheses

4j+4-16=0

We add all the numbers together, and all the variables

4j-12=0

We move all terms containing j to the left, all other terms to the right

4j=12

j=12/4

j=3

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