y+(3y+5)+(8y-20)=18

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Solution for y+(3y+5)+(8y-20)=18 equation: 



y+(3y+5)+(8y-20)=18

We move all terms to the left:

y+(3y+5)+(8y-20)-(18)=0

We get rid of parentheses

y+3y+8y+5-20-18=0

We add all the numbers together, and all the variables

12y-33=0

We move all terms containing y to the left, all other terms to the right

12y=33

y=33/12

y=2+3/4

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