10-2(3j+8)=3(2j-10)

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Solution for 10-2(3j+8)=3(2j-10) equation: 



10-2(3j+8)=3(2j-10)

We move all terms to the left:

10-2(3j+8)-(3(2j-10))=0

We multiply parentheses

-6j-(3(2j-10))-16+10=0



We calculate terms in parentheses: -(3(2j-10)), so:

3(2j-10)

We multiply parentheses

6j-30

Back to the equation:

-(6j-30)



We add all the numbers together, and all the variables

-6j-(6j-30)-6=0

We get rid of parentheses

-6j-6j+30-6=0

We add all the numbers together, and all the variables

-12j+24=0

We move all terms containing j to the left, all other terms to the right

-12j=-24

j=-24/-12

j=+2

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