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y(26-y)=0
We add all the numbers together, and all the variables
y(-1y+26)=0
We multiply parentheses
-1y^2+26y=0
a = -1; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·(-1)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*-1}=\frac{-52}{-2} =+26 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*-1}=\frac{0}{-2} =0 $
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