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1/2(x+3)=-7x=1
We move all terms to the left:
1/2(x+3)-(-7x)=0
Domain of the equation: 2(x+3)!=0We get rid of parentheses
x∈R
1/2(x+3)+7x=0
We multiply all the terms by the denominator
7x*2(x+3)+1=0
Wy multiply elements
14x^2(x+1=0
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