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y(2y-3)+234=360
We move all terms to the left:
y(2y-3)+234-(360)=0
We add all the numbers together, and all the variables
y(2y-3)-126=0
We multiply parentheses
2y^2-3y-126=0
a = 2; b = -3; c = -126;
Δ = b2-4ac
Δ = -32-4·2·(-126)
Δ = 1017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1017}=\sqrt{9*113}=\sqrt{9}*\sqrt{113}=3\sqrt{113}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{113}}{2*2}=\frac{3-3\sqrt{113}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{113}}{2*2}=\frac{3+3\sqrt{113}}{4} $
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