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1/2p=1/4p-1
We move all terms to the left:
1/2p-(1/4p-1)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
Domain of the equation: 4p-1)!=0We get rid of parentheses
p∈R
1/2p-1/4p+1=0
We calculate fractions
4p/8p^2+(-2p)/8p^2+1=0
We multiply all the terms by the denominator
4p+(-2p)+1*8p^2=0
Wy multiply elements
8p^2+4p+(-2p)=0
We get rid of parentheses
8p^2+4p-2p=0
We add all the numbers together, and all the variables
8p^2+2p=0
a = 8; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*8}=\frac{-4}{16} =-1/4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*8}=\frac{0}{16} =0 $
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