y(2y+5)+26=90

Solution for y(2y+5)+26=90 equation:

y(2y+5)+26=90

We move all terms to the left:

y(2y+5)+26-(90)=0

We add all the numbers together, and all the variables

y(2y+5)-64=0

We multiply parentheses

2y^2+5y-64=0

a = 2; b = 5; c = -64;
Δ = b2-4ac
Δ = 52-4·2·(-64)
Δ = 537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{537}}{2*2}=\frac{-5-\sqrt{537}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{537}}{2*2}=\frac{-5+\sqrt{537}}{4}
$