-3(b+1)+8(b-1)=b-8+3b-2

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Solution for -3(b+1)+8(b-1)=b-8+3b-2 equation: 



-3(b+1)+8(b-1)=b-8+3b-2

We move all terms to the left:

-3(b+1)+8(b-1)-(b-8+3b-2)=0

We add all the numbers together, and all the variables

-3(b+1)+8(b-1)-(4b-10)=0

We multiply parentheses

-3b+8b-(4b-10)-3-8=0

We get rid of parentheses

-3b+8b-4b+10-3-8=0

We add all the numbers together, and all the variables

b-1=0

We move all terms containing b to the left, all other terms to the right

b=1

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