4n+1=1-2(n-3)

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Solution for 4n+1=1-2(n-3) equation: 



4n+1=1-2(n-3)

We move all terms to the left:

4n+1-(1-2(n-3))=0



We calculate terms in parentheses: -(1-2(n-3)), so:

1-2(n-3)

determiningTheFunctionDomain
-2(n-3)+1

We multiply parentheses

-2n+6+1

We add all the numbers together, and all the variables

-2n+7

Back to the equation:

-(-2n+7)



We get rid of parentheses

4n+2n-7+1=0

We add all the numbers together, and all the variables

6n-6=0

We move all terms containing n to the left, all other terms to the right

6n=6

n=6/6

n=1

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