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x=60+5/8x
We move all terms to the left:
x-(60+5/8x)=0
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(5/8x+60)=0
We get rid of parentheses
x-5/8x-60=0
We multiply all the terms by the denominator
x*8x-60*8x-5=0
Wy multiply elements
8x^2-480x-5=0
a = 8; b = -480; c = -5;
Δ = b2-4ac
Δ = -4802-4·8·(-5)
Δ = 230560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{230560}=\sqrt{16*14410}=\sqrt{16}*\sqrt{14410}=4\sqrt{14410}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-4\sqrt{14410}}{2*8}=\frac{480-4\sqrt{14410}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+4\sqrt{14410}}{2*8}=\frac{480+4\sqrt{14410}}{16} $
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